Three identical blocks connected by ideal strings are being pulled along a horizontal frictionless surface by a horizontal force F. The magnitude of the tension in the string between blocks B and C is T= 3.00N . Assume that each block has mass m= 0.400kg.

What is the magnitude F of the force?

What is the tension T(AB) in the string between block A and block B?

http://session.masteringphysics.com/prob%E2%80%A6

### 2 Answers

Three identical blocks connected by ideal strings are being pulled along a horizontal frictionless surface by a horizontal force F. The magnitude of the tension in the string between blocks B and C is T= 3.00N . Assume that each block has mass m= 0.400kg.

The force, F, is causing all 3 blocks to accelerate at the same rate. The tension in the string between blocks B and C is caused by the horizontal force, F, which is pulling all 3 blocks.

The string between blocks B and C is pulling blocks B and A. The 3.00 N force is causing the mass of B + A to accelerate.

F = m * a

3.00 = 0.800 * a

Acceleration = 3.00 ÷ 0.800 = 3.75 m/s^2

This is the acceleration of all 3 blocks!

The horizontal force, F = (mass of 3 blocks) * 3.75

F = 1.2 * 3.75 = 4.5 N

T(AB) is only pulling block A.

T(AB) = 0.4 * 3.75 = 1.5 N

The tension force increase as more mass is being accelerated!

Source(s): i found same q some where 30 min back and the answer is also from there onlyMastering Physics Pulling Three Blocks

Source(s): https://owly.im/a0cjp