a) 2 – 2 sqrt (6) – 3
b) 1
c) 2 + 2 sqrt (6) – 3
d) 5
Simplify: 2 sqrt (3) + 4 sqrt (3)
a) 18
b) sqrt (9)
c) 8 sqrt (3)
d) 6 sqrt (3)
Simplify: sqrt (12) – sqrt (27)
a) – sqrt (15)
b) 5 sqrt (3)
c) 15 sqrt (3)
d) sqrt (3)
Solve: sqrt (3)b + sqrt (2) = sqrt (7)b – 10
a) none
b) (3)
c) (3)
d) (4)
Solve: 4 sqrt (x) = 8 + 2 sqrt (x)
a) (4)
b) (16)
c) none
d) (4)
Solve: t – sqrt (6)t – 9 = 0
a) (3,3)
b) 0
c) (3)
d) (3)
Solve: sqrt (t) – 1 + 3 = 9
a) (7)
b) none or 0
c) (35)
d) (37)
Solve: sqrt (m) + 7 = 5
a) none or 0
b) (2)
c) (4)
d) (2)
simplify: sqrt (75)
a) (3) sqrt 5
b) (3) sqrt 25
c) (3) sqrt 2
d) (5) sqrt 3
6 Answers

Dude am i doing your home work for you????
WDH i’m bored. Here goes.
1. b
2. d
3. d
4. a (Have reservations about this question’s format)
5. b
6. Either not correct or too complex for the scope of the remaining questions except you meant to write t^2 – sqrt (6)t – 9 = 0 in which case it is solved quadratically.
7. b
8. c
9. d

Sqrt 2 Sqrt 3

Well, for the first one you get to FOIL!! And any day you get to FOIL is a good day!! (Remember that!) If you are not familiar with the FOIL technique, check out this video: http://www.youtube.com/watch?v=8h_lHZgVq_8
After you do that on the first question, you end up with sqrt(2)*sqrt(2) + sqrt(3)*sqrt(3). Now, a square root is simply the opposite of a square…so if you are squaring a square root, you end up with the original number, right?
This means that you have 2 + 3 = 5 for your first problem.
For the rest of those problems, you need to look at the square root rules, http://www.mathwords.com/s/square_root_rules.htm.
These rules allow you to break a square root down into the smallest numbers possible. Remember, a proper square root is an irrational number, which means that it can’t be broken down into any other combination of numbers.

1) B
2) D
3) D
4) A
5) C
6) A
7) B
8) A
9) D

top one is SQRT + 4.
like, the title one. 🙂

mmm… someone is too lazy to do their own homework 🙁