# Solve this equation: 2s + s + 12 = 132?

A. s = 120

B. s = 40

C. s = -30

D. s = 9

I'm thinking B/40 ??? Any opinions. I'm trying so hard to understand this algebra stuff, never took it in high school many of years ago, and now going back to school to get my diploma. any help is so much appreciated.

• 2s + s + 12 =132

3s +12 =132

3s = 120

s = 40

• This is a simple question-

2s+s+12=132

From (A.) substitute the value of s

2(120) + 120+ 12

2* 120+120+12 will not be equal to 132

similarly,

in option B,

2(40) + 40+ 12 = 132

2*40 +40+12=132

132 = 132

LHS = RHS

Hence proved

Similarly try for all other options!

If LHS = RHS,

Then the equation is correct

Good Day

• Yes, S = 40.

Here is how to get it.

2S + S + 12 = 132

2S + S = 132 - 12

3S = 120

S = 120 / 3

S = 40

Intro to Algebra is easy as long as you know your multiplication Table and remember to change the sign when you move numbers or sign to the other side of the equal sign.

Good luck on your diploma. =)

• 2s+s+12=132 First you combine like terms

3s+12=132 Then you subtract 12 from both sides

3s=120 Then you divide by 3 on both sides

s=40

• Think of the single "s" as being "1s". So,

2s + 1s + 12 = 132

Get the 12 on the other side of the equals sign by subtracting (since 12 is positive on the one side, you would just reverse signs to get it on the other side. If it were negative, then you would add 12). Anything you do on one side of the equals sign you will do on the other side:

2s + 1s + 12 - 12 = 132 - 12

2s + 1s = 120

Then, you can add the s values:

2s + 1s = 120

3s = 120

Now you solve for s. Since 3s is really 3 times s (3 X s), you would divide by 3 to get the value of just s. Again, what you do on one side of the equals sign you do on the other:

3s/3 = 120/3

s = 40

Hope this helps.

• 12 - 132 = 120. 3s=120 divide S= 40

• 2s + s + 12 = 132

3s + 12 = 132

3s = 132 - 12

3s = 120

s = 120/ 3

s = 40

so it is B

• 2s + s+ 12 =132

3s +12 = 132

3s = 132 - 12

3s = 120

s = 120/3

s = 40