# Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. your calculator answer would be 11.76 cm2

Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. your calculator answer would be 11.76 cm2 . now suppose you are asked to enter the answer to two significant figures. (note that if you do not round your answer to two significant figures, your answer will fall outside of the grading tolerance and be graded as incorrect.)

12 square cm correct to 2 significant figures

Step-by-step explanation:

Area of a Rectangle = L X B = 2.1 X 5.6 = 11.76 square cm

To round your result to 2 significant figure, we start counting from the left from the first non-zero digit.

The first two digits are 11 but because the number after is 7 (greater than 4), we round up to 12.

11.76 square cm = 12 square cm correct to 2 significant figures Step-by-step explanation:

We are given that

Width of rectangle=b=2.1 cm

Length of rectangle=l=5.6 cm

We have to find the area of rectangle.

We know that

Area of rectangle= Using the formula

Area of rectangle = Area of rectangle= Hence, the area of rectangle= Area can be calculated by multiply these two numbers 2.1-cm and 5.6 –cm and got 11.76 cm 2.

Further Explanations:

Area Calculation

Area of square:

Area can be calculated by multiplying the base and height it depends on you that which area is you want to calculate. If you want to calculate the AREA OF SQUARE

That formula for square is side of square is multiplied by side of the sane square.

Area of Triangle:

If you want to calculate the area of the rectangle than you have to use he formula of ½ * Base* Height.

Area of rectangle:

If you want to calculate the area of rectangle than area of rectangle can be calculated by formula as base * Height. Because rectangle ha two side equals

Two significant figures:

The condition of the question is this that there should be only two significant numbers means after the do of the number there are only two digits.If you have more than digits than the rules of  significant digits should be applied on them.

Subject: Physics

Level: Middle School

Key Words:

Area of square

Area of Triangle

Area of rectangle:

Two significant figures

For further Evaluation:

The area of a rectangle whose length is 5.6 cm and the width is 2.1 cm to two significant figures is 12 cm ².

Further Explanation Area Area is a measure of how much space is occupied by a given shape.Area of a substance is determined by the type of shape in question.

For example;

Area of a rectangle is given by; Length multiplied by width

Area of a triangle = 1/2 x base x height

Area of a circle = πr². where r is the radius of a circle,

Area of a square = S², Where s is the side of the square.etc.

Perimeter

Perimeter is defined as the distance along a two dimension shape.  Perimeter of different shapes is given by different formulasFor example

The perimeter of a rectangle = 2(length+width)

The perimeter of a triangle = a+b+c; where a, b and c are the sides of the triangle. etc.

In this question

The rectangle has a;

Length = 5.6 cm

Width = 2.1 cm

Area of a rectangle = length × width

= 2.1 cm × 5.6 cm

= 11.76 cm²

The area of the rectangle to two significant figures is 12 cm²

Keywords; Area, Area of a rectangle

Level: Middle school

Subject; Mathematics

Topic: Area and Perimeter

The area of the rectangle is 12 cm² ⇒ in 2 significant figures

Step-by-step explanation:

* Lets talk about the significant figures

- All non-zero digits are significant

# 73 has two significant figures

- Zeroes between non-zeros digits are significant

# 105.203 has six significant figures

- Leading zeros are never significant

# 0.00234 has three significant figures

- In a number with a decimal point, zeros to the right of the last

non-zero digit are significant

# 19.00 has four significant figures

- Lets make a number and then approximate it to different significant

∵ 12.7360 has 6 significant figures

∴ 12.736 ⇒ approximated to 5 significant figures

∴ 12.74 ⇒ approximated to 4 significant figures

∴ 12.7 ⇒ approximated to 3 significant figures

∴ 13 ⇒ approximated to 2 significant figures

∴ 10 ⇒ approximated to 1 significant figure

- Another number with decimal point

∵ 0.0546700 has 6 significant figures

∴ 0.054670 ⇒ approximated to 5 significant figures

∴ 0.05467 ⇒ approximated to 4 significant figures

∴ 0.0547 ⇒ approximated to 3 significant figures

∴ 0.055 ⇒ approximated to 2 significant figures

∴ 0.05 ⇒ approximated to 1 significant figures

* Lets solve the problem

∵ The width of the rectangle is 2.1 cm

∵ The length of the rectangle is 5.6 cm

- Area of the rectangle = length × width

∴ Area of the rectangle = 2.1 × 5.6 = 11.76 cm²

- Approximate it to two significant figures

∴ Area of the rectangle = 12 ⇒ to the nearest 2 significant figures

* The area of the rectangle is 12 cm² ⇒ in 2 significant figures

If I’m understanding the question then 11.76cm^2 in two sig figs is 12cm^2. I don’t see a part c to this question though so if I’m not giving you the answer you need please advise and I will answer what you need! Thank you!!

12 cm²

Step-by-step explanation:

Length of rectangle = 5.6 cm

Width of rectangle = 2.1 cm

Area of rectangle = Length of rectangle×Width of rectangle

⇒Area of rectangle = 5.6×2.1

⇒Area of rectangle = 11.76 cm²

11.76 has 4 significant figures in order to write this term in 2 significant terms we round of the term

The last digit in the decimal place is 6. Now, 6≥5 so we round the next digit to 8 we get

11.8

Now the last digit in the decimal place is 8. Now, 8≥5 so we round the next digit to 2 we get

12

∴ Hence the area of the rectangle when rounded to 2 significant figures is 12 cm²

The significant figures need to be counted from first non-zero number at left. So put the 11.76 to two significant figures is 12. The unit is cm2. So the answer is 12 cm2.
1) ALL non-zero numbers (1,2,3,4,5,6,7,8,9) are ALWAYS significant.2) ALL zeroes between non-zero numbers are ALWAYS significant.3) ALL zeroes which are SIMULTANEOUSLY to the right of the decimal point AND at the end of the number are ALWAYS significant.4) ALL zeroes which are to the left of a written decimal point and are in a number >= 10 are ALWAYS significant.

so it will be 11.76 = 12 bc 7 rounds up

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