The combustion of propane (C3H8) in the presence of excess oxygen

The combustion of propane (C3H8) in the presence of excess oxygen yields CO2 and H2O:

C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g)

When 7.3 g of C3H8 burns in the presence of excess O2, ____ g of CO2 is produced.

1 Answer

  • 7.3 g C3H8 x 1mole C3H8 / 44.0 g x 3 moles CO2/1mole C3H8 = 0.498 moles CO2

    0.498 moles CO2 x 44.0 g CO2 / 1mole CO2 = 21.9 g CO2

    Answer 22 grams with two significant figures.

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