The expression P(4, 3) is equal to: A. 3! B. 4! C. 1?

2. Evaluate P(7, 1).

A. 1

B. 7

C. 5,040

3. If you divide 6! by 4! you are evaluating

A. P(6, 4)

B. P(4, 6)

C. P(6, 2)

THANK YOU FOR THE HELP! i’ve been stuck on theses three for 4 days!

2 Answers

  • It sounds like you are asking about permutations. In other words, how many ways can you choose 3 items from 4 items in specific orders.

    The formula is: nPr = n! / (n-r)!

    In your notation, that would be P(n,r)

    1. 4P3 = 4! / (4-3)! = 4! / 1! = 4! = 24

    2. 7P1 = 7! / 6! = 7

    3. 6! / 4! = 6! / (6 – 2)!

    n = 6

    r = 2

    6P2 or P(6,2) in your notation.

    If the question asks about “combinations” where order does not matter, the formula is

    nCr = n! / (n-r)! / r!

  • P(4, 3) = 4! / (4 – 3)! = 4! / 1! = 4!

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