### 7 Answers

I think you mean Consecutive integers (integrals are calculus material)

So:

x + (x+1) + (x+2) = 117

3x + 3 = 117

3x = 114

x = 38

so, 38, 39, 40

38+39+40 = 117

Source(s): ðŸ™‚ xx+(x+1)(x+2)=117

x+x+1+x+2=117

3x + 3 = 117

3x = 114

x = 38

38+1 = 39

38+2 = 40

Check 38+39+40 = 117

so three consecutive integral numbers are 38 ,39 and 40

Let the three consecutive numbers be n-1, n, n+1 then their sum is 3n i.e. 3n=117 therefore n=39 and the three numbers are 38, 39,40

a+b+c=117

b=a+1

c=a+2

a+a+1+a+2=117

Therefore: 3a=117-3=114 . So a=38

The numbers are: 38, 39 and 40.

38, 39 and 40

n + (n+1) + (n + 2) = 117

3n + 3 = 117

3n = 114

n = 38

so 38, 39, 40