Two people are carrying a uniform wooden board that is 3.00 m
longand weighs 160 N. If one person applies an upward force equalto
60 N at one end, at what point does the other person lift? Begin
with a free body diagram of the board.

## Answer

2.00 m 1.5m F 60 N 2. W 160N The weight of the wooden board is, W- 160 N Force applied by one person is, F 60 N Hence the force applied by the other personis, F-100 N

The torque applied by both the forces at the centre of the bar must balance with each other. (60 N) (1.5 m)-(100 N)(d2) Solving the above expression for dh, d, 0.9 m d+d 1.5 m+0.9 m-2.4 m Hence the force applied by the second person should be at a distance of 2.4 m from the first end of the bar

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