Use the given molar solubilities in pure water to calculate ksp for each compound. part a bacro4; molar solubility =1.08×10−5m

Use the given molar solubilities in pure water to calculate ksp for each compound. part a bacro4; molar solubility =1.08×10−5m

Answers

When BaCrO4 dissolves, it dissociates like this: BaCrO4 (s) --> Ba2+ + CrO42-

The expression for Ksp is [Ba2+] x [CrO42-]

There is a 1:1 molar ratio between the BaCrO4 that dissolves and Ba2+ and CrO42- that are in solution. This means that, when 1.08×10⁻⁵ moles per liter of BaCrO4 dissolves, it produces 1.08×10⁻⁵ mol/L of Ba2+ and 1.08×10⁻⁵ of  CrO42-. So, applying the expression:

Ksp = (1.08×10⁻⁵ ) x (1.08×10⁻⁵ )
= 1.166 x 10⁻¹⁰

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You use the atomic number to find out how many protons and neutrons there are in the atom. you use the atomic mass to find out how many protons and electrons there are in the atom. 

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