We dissolve 2.45 g of sugar in 200.0 g water. what is the mass percent of sugar in the solution?


8. We dissolve 2.45 g of sugar in 200.0 g water. What is the mass percent of sugar in the solution? (A)1.21% B) 1.23% C) 2.42% D) 123% E) none of the above 9. What is the mass percent of a solution prepared by dissolving 18.9 grams of solid into 39.5 grams of water? A) 47.8g。 )58.4% 32.4% D) The identity of the compound must be known. E) none of the above 10. What is the molarity of a solution prepared by dissolving 10.7 g Nal in 0.250 L? A) 42.8 B) 0.0714 2.86x104 D) 0.286 E) none of the above Please solve the equations with full explanation

Answer

General guidance

Concepts and reason

The concept used to solve this problem is based on the concentration of a solution.

The concentration of a solution is expressed in a number of ways, such as molarity, mass percent, etc.

Fundamentals

The mass percentage of an element in a compound is the number of parts by mass of that element present in 100 parts by mass of the compound. It can be calculated by using the following equation:

001*** = % …… (1)

Here, is the mass percentage of the solute, is the mass of the solute and is the mass of the solution.

The number of moles of a substance is calculated by using the expression,

W
=U …… (2)

Here, is the number of moles of a substance, is the mass of the substance and is the molar mass of the substance.

Molarity (M) is described as the number of moles of solute present in one liter of solution. It is expressed as follows:

MV (L) …… (3)

Here, n is number of moles of solute and V is volume of solution in liter.

Step-by-step

Step 1 of 3

(8)

The mass of solution is calculated by adding the mass of sugar and the mass of water as follows:

M, =m, um

Here, is the mass of the solution, is the mass of sugar and is the mass of water.

Substitute 2.45 g for and 200.0 g for .

M = 2.45 g +200.0 g
= 202.45 g

Use equation (1) to determine the mass percent of sugar.

Substitute 2.45 g for and 202.45 g for .

2.45 g x100
%
=
202.45 g
= 1.21%

Part 8

The mass percent of sugar in the solution is 1.21%.


The mass of solution is determined by adding the mass of water and mass of solution. Furthermore, substitute the mass of solution and mass of sugar in equation (1) to calculate the mass percent of sugar in the solution, which is determined to be .

Step 2 of 3

(9)

The mass of solution is calculated by adding the mass of solid and the mass of water as follows:

M, =m, um

Here, is the mass of solution, is the mass of solid and is the mass of water.

Substitute 18.9 g for and 39.5 g for .

M=18.9 g +39.5 g
= 58.4 g

Use equation (1) to determine the mass percent of solution.

Substitute 18.9 g for and 58.4 g for .

0-18.98 x100
58.4 g
= 32.4%

Part 9

The mass percent of the solution is 32.4%.


The mass of solution is determined by adding the mass of solid and the mass of water. Furthermore, substitute the mass of solution and the mass of solid in equation (1) to calculate the mass percent of solution, which is determined to be .

Step 3 of 3

(10)

Use equation (2) to determine the number of moles of sodium iodide as follows:

Substitute 10.7 g for and 149.89 g/mol for .

n
10.7 g
=
149.89 g/mol
= 0.0714 mol

Use equation (3) to determine the concentration of solution.

Substitute 0.0714 mol for and 0.250 L for .

0.0714 mol
0.250 L
= 0.286 M

Part 10

The molarity of the solution is 0.286 M.


The number of moles of sodium iodide is calculated by using equation (2) and substituting the mass of sodium iodide and molar mass of sodium iodide. Furthermore, by using equation (3) and substituting the values of number of moles of sodium iodide and volume of solution, the molarity of solution is determined to be .

Answer

Part 8

The mass percent of sugar in the solution is 1.21%.

Part 9

The mass percent of the solution is 32.4%.

Part 10

The molarity of the solution is 0.286 M.

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