What are the signs of delta S, delta H, and delta G for the formation of dew on a cool night?
In the process of formation of dew, water changes from gaseous state to liquid state. The gaseous state is more disorder (entropy is high) as compared to liquid state (entropy is low). This means the process goes from higher entropy to lower entropy. Therefore, the change of entropy is negative. Therefore, the sign of AS will be negative. The phase change of any substance from gaseous to liquid occurs with the loss of heat. This means formation of dew is an exothermic process. The sign of enthalpy for exothermic process is negative. AH-ve Since, the formation of dew is a spontaneous process. Therefore, the free energy change for this process is also negative. Hence, the correct responses arel-AS,-ΔΗ:-AG