What average force is needed to accelerate a 7.00-gram pellet from rest to 125 m/s^2 over a distance of 0.800m along the barrel of a rifle?

2 Answers

  • Initial velocity, u = 0

    Final velocity, v = 125 m/s

    Distance, s = 0.8 m

    Mass, m = 7 gram = (7/1000) kg

    v^2 = u^2 + 2as

    Or, v^2 = 2as [u = 0]

    a = v^2 / (2s) = (125)^2 / (2 × 0.8)

    Required force, F = ma

    Put the values of m and a, then use calculator. You will get, F = 68.359375 N

  • a = V^2/2d = 125^2/1.6 = 9,766 m/sec^2

    F = m*a = 9.766*7.0 = 68.36 N

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