A 50kg- parachute jumper descends at a steady 40 km/h.

What is the force of air on the parachute? help!!!!

### 5 Answers

As there is a CONSTANT speed of 40 km/h, then there is no acceleration. Therefore the force of air on the parachute = force of jumper’s weight.

Weight = mass

*9.8 = 50*9.8 = 490NTherefore Force of air resistance = 490N

f=ma m=50 a=9.8

so F( on parachute) =50 * 9.8 = 490 N

That’s not actually correct

so happy that I found this question already answered! It is like you’ve read my thoughts!

50×9.8=490newtons