What is the free-fall acceleration on planet 2?

The free-fall acceleration at the surface of planet 1 is 22 m/s2. The radius and the mass of planet 2 are twice those of planet 1.

What is the free-fall acceleration on planet 2?

1 Answer

  • g1 = G M1/R1^2

    g2 = G M2/R2^2


    g2/g1 = [M2/M1] [R1/R2]^2

    g2/g1 = [2 M1/M1] [R1/2 R1]^2

    g2/g1 = [2] [1/4] = 1/2

    g2 = g1/2 = 22/2

    g2 = 11 m/s^2

Leave a Comment