What is the magnitude of the net torque on the pulley about the axle?

## Answer

let,

force F1=20 N

force F2=30 N

diameter of the pully d=4cm

radius of the pully r=d/2=2cm

net torque =(r*F2)-(r*F1)

=r*(F2-F1)

=0.02*(30-20)

=0.2 N.m ----is answer

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