What is the mass in grams of 0.250 mol of the common antacid calcium carbonate?

4.00 × 10^2 g

25.0 g

17.0 g

4.00 × 10^-2 g

2.50 × 10^-3 g

1 Answer

  • Molar mass CaCO3 = 100 g/mol

    100 x 0.250 = 25.0 g

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