What is the probability that Bo, Colleen, Jeff and Rohini win the first, second, third and fourth prizes, respectively (in that order),

What is the probability that Bo, Colleen, Jeff and Rohini win the first, second, third and fourth prizes, respectively (in that order), in a drawing if 50 people enter a contest and 4a) no one can win more than one prize. 4b) winning more than one prize is allowed.

Answers

1/4669920

Step-by-step explanation:

First if all, when repetition is mot allowed, we use Permutation to get the number of possible outcomes as follows;

P(n, r) = n!/(n - r)!

Now, the order is important since the first, second, third and fourth prizes are different.

Thus, we need to define the Permutation.

We need to select 4 winners of the 48 people.

Thus, n = 48 and r = 4

Thus;

P(48,4) = 48!/(48 - 4)!

P(48,4) = 4669920

Now, probability is the number of favourable outcomes divided by number of possible outcomes

Thus,

Probability = 1/4669920

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