Mars rotates on its axis once every 24.8 hours.

Part A

What is the speed of a geosynchronous satellite orbiting
Mars?

Part B

What is the altitude of a geosynchronous satellite orbiting
Mars?

## Answer

This question is difficult and kind of confusing. I will show you the solutions:a) Mass of mars: 6.4191×10^23 kg

F_centripetal = F_gravitational

m_s * a_g = m_s * a_c

Note: m_s is the mass of satellite, a_g is gravitational acceleration, and a_c is centripetal acceleration

Mass of satellite cancels out from the above equation and why the mass of satellite is not even given to you in the first place.

Therefore, a_g=a_c

a_c = (omega)^2*r

a_g = GM/r^2 <—–M is the mass of Mars

(omega)^2*r = GM/r^2

r^3=GM/(omega)^2

r= cubic root {GM/(omega)^2}

speed of a geosynchronous satellite = (omega)*r = (omega)*cubic root {GM/(omega)^2} = cubic root (GM*omega)

Note: simplified using the fact that omega can also be written as cubic root (omega^3)

Also know that T=2pi/omega

or omega = 2pi/T

speed of a geosynchronous satellite =cubic root (GM*omega)= cubic root (GM2pi/T)

= cubic root [(6.673 x 10^-11 x 6.4191×10^23 kg x 2 x pi) / (24.8hours x 3600 seconds/hr)]

= 1440 m/s = 1.44km/s

b) v=omega*r

r=v/omega

omega = 2pi/T=2*3.14/(24.8hours x 3600 seconds/hr)]

v= 1440m/s from part a

r=2.05*10^7

But radius of mars is 3397000m

Altitude = 2.05*10^7-3397000=1.72*10^7m