A + 10 nC charge is located at the origin.
part A: What is the strength of the electric field at the
position (*x*,*y*)=(5.0cm,0cm)?
Part B: What is the strength of the electric field at the
position (*x*,*y*)=(−5.0cm,5.0cm)?
Part C: What is the strength of the electric field at the
position (*x*,*y*)=(−5.0cm,−5.0cm)?

## Answer

Solution: Part A The strength of the field at the point, (x, y)- (5cm,0cm) Since, the distance from the charge to that point is, )2 -10.05), (0 = 0.05 m Let the electric field strength at the above point is, E= 10 1010) 98109)(10×10-9 (0.05) 3.6×104 N/C Hence, the strength of the electric field at the position (x, y)- (5cm,0cm)is 3.6×10 N/C

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Part C The strength of the field at the point, (x, y)- (-5cm,-5cm) Since, the distance from the charge to that point is, V-0.05)(-0.05) 0.071m Let the electric field strength at the above point is, kq (910′)(10×10″) (0.01) -1.8×101 NC Hence, the strength of the electric field at the position (x, y) -(-5cm.-5cm)is 1.8×104 N/C