What is the value of 36x – 8y² when x = 3 and y = -6?

11 Answers

  • You just plug in these numbers for variables. For instance:

    36(3)-8(-6)^2=

    108-288=

    -180

    Hopefully, that helps you.

    Hooah!

  • Find 36x – 8y^2 when x = 3 and y = -6

    Replacing variables with values:

    36*(3) – 8*(-6)^2

    =108 – 8*(36) ( (-6)^2 = 6^2, whenever a negative number is raised to an even power, it becomes positive)

    = 108 – 288

    = -180

    Thus, the result is (-180)

  • 36x – 8y^2

    when x= 3 & y = – 6

    so 36x – 8y^2 = 36*3- 8*36= 36[ 3- 8]

    =- 36*5 = – 180

  • 36x – 8y² when x = 3 and y = -6

    = 36(3) – 8(-6)^2

    = – 180 answer..

  • 36x-8y^2 = 36(3) – 8(-6)^2 = 108-8(-6)^2 = 108-288 = -180.

  • Just put the values and calculate… it is 36*3 -8*(-6)^2 = 108 – 288 = – 180 OK!

  • 36*3 – 8*(-6)^2

    = 108 – 8*36

    = 108 – 288

    = -180 <<<

  • value is 36(3) – 8(-6)^2

    = 36(3) – 8(36)

    = 36(3 – 8)

    = 36(-5)

    = -180

  • -180

  • -180

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