What is the wavelength of light having a frequency of 4.8X10^14 s^-1 (c=3.0X10^8m/s)?

What are the steps to solve this and what does c stand for exactly. Thank you in advance. (Studying for chem exam)

1 Answer

  • the general equation is v = f lambda

    where v is speed in m/s, f is frequency in Hz (s^-1) and lambda is wavelength in m

    but c is the speed of light


    c - f lambda

    3.0E8 = 4.8E14 *lambda

    lambda = 6.25E-7 m or 625 nm

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