What mass of Na2SO4 is needed to make 2.5 L of 2.0 M solution?

(molar mass of Na = 23; S = 32; O = 16)

A. 178 g

B. 284 g

C. 356 g

D. 710 g

2 Answers

  • Molar mass Na2SO4 = 142 g per mol.

    142 g in 1L is 1.0M,

    142 * 2 g in 1L = 2.0M,

    142 2 2.5 g in 2.5 L is 2.0M.

    142 2 2.5 = 710.

    The correct answer is D. 710 g.

  • The molar mass of sodium sulfate is(rounded off): 142 g/mole. A 1 M solution will be 142 g/liter of solution; a 2M solution will be284 g/liter of solution; 2.5 liters of solution will requires 2.5 X 284 grams or 710 grams

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