What value of x is in the solution set of 4x – 12 ≤ 16 8x?

What value of x is in the solution set of 4x – 12 ≤ 16 8x?

Answers

we have

4x-12leq 16+8x

The options of the question are

-10 -9 -8 -7

Group terms that contain the same variable, and move the constants to the opposite side of the inequality

-12-16leq 8x-4x

-28leq 4x

rewrite the inequality

4xgeq -28

Divide by 4 both sides

xgeq -7

The solution is the interval-------> [-7,∞)

All real numbers greater than or equal to -7

therefore

the answer is

-7

There is an operator missing.

I will assume that the right inequality is 4x - 12 ≤ 16 + 8x

4x - 8x ≤ 16 +12

- 4x ≤ 28

x ≥ - 28/4

x ≥ - 7

-0.6

Step-by-step explanation:

-7

Step-by-step explanation:

-7

Step-by-step explanation:

4x-12=16+8x

-12-16=8x-4x

-28÷4=x

x=-7

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