# Which function is positive for the entire interval [-3,-2]?

Which function is positive for the entire interval [-3,-2]?

B

Step-by-step explanation:

C

Step-by-step explanation:

On a coordinate plane, a curved line with a minimum value of (2, 4) and a maximum value of (0.5, 6), crosses the x-axis at (negative 1.5, 0) and crosses the y-axis at (0, 5).

Step-by-step explanation:

c

Step-by-step explanation:

a   b

c   d

so c

Graph 2 represents that the  function is positive for the entire interval [-3, -2].

Step-by-step explanation:

We are given four different graphs for different functions. We have to find the graph that is positive for the entire interval [-3,-2].

We make the following observation from the given graphs.

In graph 1, the function has a value of 0 at -3 and and the value decreases from -3 to -2. Thus, the function is negative in the given interval.In graph 2, it can be clearly seen that the function has a positive value, through the entire given interval.In graph 3, the function shows negative value entirely in the given interval.In graph 4, the function exhibits both positive and negative value in the given interval and in not positive in the entire interval.

Thus, function in graph 2 is positive for the entire interval [-3, -2].

Graph B

Step-by-step explanation:

We are given 4 graphs.

We need to find the function graph which is positive of the entire interval [-3, -2]

It is a closed interval. So it is inclusive of -3 and -2

In these interval the graph of y value must be in positive region.

By looking at the graph, the graph B has positive y-values in the entire interval [-3, -2]

Therefore, the answer is Graph B)

The interval [–3, –2] contains only negative numbers

We have to determine a function that is positive for the entire interval.

There can be several such functions; however, the basic condition that needs to be met for a function to be positive for the interval [–3, –2] is that it should be multiplied by (-1)

Hence, one such function that is positive for the entire interval is f(x) = -x

You must add the graphs for this equation

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