Write balanced complete ionic equation for the reaction cas(aq)+cucl2(aq)→cus(s)+cacl2(aq).

Write balanced complete ionic equation for the reaction and Write balanced net ionic equation for the reaction

1. CaS(aq)+CuCl2(aq)?CuS(s)+CaCl2(aq)

2. NaOH(aq)+HNO3(aq)?H2O(l)+NaNO3(aq)

3. 2K3PO4(aq)+3NiCl2(aq)?Ni3(PO4)2(s)+6KCl(aq) .

Answer

General guidance

Concepts and reason
The concept used in this problem is based on a double displacement reaction. Double displacement reaction is a chemical reaction in which two compounds react in an aqueous medium are dissociate, forming cations and anions which exchange places, resulting in two new products.

Firstly, write the constituent ions of each reactant in an aqueous medium that taking part in a chemical reaction. After that, write an ionic equation andnet ionic equation.

Fundamentals

Double displacement reaction:

In a double displacement reaction, two ionic compounds(reactants) exchange their ions and formed two new compounds.

Example –

AX + BY → BX + AY

Balanced chemical reaction:

A balanced chemical reaction is a reaction in which the number of atoms at the reactant side is similar to the number of atoms at the product side in the same reaction.

Complete ionic equation:

An ionic equation is a type of chemical equation in which all the dissociated ions of the soluble salts in the reaction are present.

Spectator ion:

These are the ions which are present on reactant as well as the product side of the ionic equation of the chemical reaction.

Net ionic equation:

In the net ionic equation, the same ions in reactant and product side get cancel out as they essentially don’t participate in the chemical reaction because they are spectator ions.

Step-by-step

Step 1 of 6

(1)

Dissociation of in an aqueous medium is shown below.

CaS(aq) → Cat (aq)+$?- (aq)

Dissociation of CuCl2in an aqueous medium is shown below.

CuCl, (aq) + Cu?* (aq)+2C1 (aq)

Dissociation reaction of the products is shown below.

Dissociation of CaCl,in an aqueous medium is shown below.

CaCl, (aq) + Ca²+ (aq)+2CF (aq)

Calcium sulfide ()is a soluble salt in aqueous solution, it will dissociate into its ions andCopper chloride is also soluble in aqueous medium, it will also dissociate into its ions and then, there are two chlorine atom present in copper chloride is balanced by putting a coefficient in front of .

In the above reaction and are cations, and are anions. So, both the reactants in aqueous solution exchange their ion, forming the precipitate of copper sulfide and aqueous calcium chloride.

Step 2 of 6

The ionic reaction is shown below.

Ca** (aq)+s?- (aq) + Cu** (aq)+2C1 (aq) + CuS(s)+Ca** (aq) + 2Cl (aq)

The net ionic reaction, occur between calcium sulfide and copper chloride, after canceling the spectator ions is shown below.

Cap (aq)+8?- (aq) +Cu²(aq) + 2er (aq) → CuS($)+Ca* (aq) + 2CT (aq)

The net ionic reaction will be shown below.

Cu* (aq)+S- (aq) → CuS(s)

Part 1

The ionic reaction is shown below.Ca** (aq) +S? (aq)+Cu²+ (aq)+2CT (aq) → CuS(s)+Ca** (aq) + 2CI+ (aq)

The net ionic reaction will be shown below.

Cu²+ (aq) +S?- (aq) → CuS(s)


As the constituent ions of calcium sulfide and copper chloride swap their places, resulting in two new products are formed. The product formed is the precipitate of copper sulfide. Another product is aqueous calcium chloride which is also soluble in water. It also dissociates into its constituent ions in the ionic equation.

In the given ionic equation, the calcium ion and chloride ion are present in the same form on both the side of the arrow of the equation. Hence, they do not contribute to the chemical reaction. So, the resultant net ionic reaction can be obtained.

Step 3 of 6

(2)

Dissociation of NaOHin an aqueous medium is shown below.

NaOH(aq) → Nat (aq) +OH(aq)

Dissociation of HNO,in an aqueous medium is shown below.

HNO3(aq) → H+ (aq)+NO; (aq)

Dissociation reaction of the products is as follows.

Dissociation of NaNO,in an aqueous medium is shown below.

NaNO3(aq) → Na*(aq) + NO, (aq)

Sodium hydroxide (NaOH) is a soluble salt in aqueous solution, it will dissociate into its ions andNitric acid () is also soluble in aqueous medium, it will also dissociate into its ions and.

In the above reaction and are cations, and are anions. So, both the reactants in aqueous solution exchange their ion, forming the water and aqueous sodium nitrate.

Step 4 of 6

The ionic reaction is shown below.

Na (aq)+OH (aq)+H* (aq)+NO, (aq) → H,0()+Na* (aq) + NO, (aq)

The net ionic reaction occurs between sodium hydroxide and nitric acid, after canceling the spectator ions is shown below.

Na (aq)+OH(aq)+H* (aq)+ No, (aq) → H20(1)+Na (aq)+ no, (aq)

The net ionic reaction will be shown below.

H(aq) +OH(aq) → H2O(1)

Part 2

The ionic reaction is shown below.

Nat (aq) +OH(aq)+H+ (aq)+NO, (aq) → H,0(1)+Na* (aq)+NO, (aq)

The net ionic reaction will be shown below.

(oʻH+ (hp) H0+(bp).H


As the constituent ions of sodium hydroxide and nitric acid swap their places, resulting in two new products are formed. The product formed is water and aqueous sodium nitrate which is also soluble in water and hence it also dissociates into its constituent ions in the ionic equation.

In this ionic equation, the sodium ion and nitrate ion are present in the same form in both the side of the arrow of the equation and hence they do not contribute to the chemical reaction. Spectator ions get to cancel out and the resultant net ionic reaction can be obtained.

Step 5 of 6

(3)

Dissociation of K,PO,in an aqueous medium is shown below.

K,PO,(aq) → 3K+ (aq) +PO, (aq)

Dissociation of NiCl2inan aqueous medium is shown below.

Nicl,(aq) Nit (aq) + 2C1 (aq)

Dissociation reaction of the products is as follows.

Dissociation of in an aqueous medium is shown below.

KCl(aq) →K*(aq) +CI+ (aq)

Potassium phosphate (K,PO,) is a soluble salt in aqueous solution, it will dissociate into its ions andNickel chloride (NiCl2) is also soluble in aqueous medium, it will also dissociate into its ions and.

In the above reaction and are cations, and are anions. So, both the reactants in aqueous solution exchange their ion, forming the precipitate of nickel phosphate and aqueous potassium chloride.

Step 6 of 6

The ionic reaction is shown below.

6K+ (aq)+P0,- (aq)+3Nit (aq)+6CI (aq) → Na PO,(s)+6K+ (aq) +6CI(aq)

The net ionic equation occurs between sodium hydroxide and nitric acid, after canceling the spectator ions is shown below.

6K* (aq) +PO,(aq)+3Ni+ (aq)+6CF (aq) → Na PO,($)+6K+ (aq) + 6CT (aq)

The net ionic reaction will be shown below.

3Nit (aq)+PO,- (aq) → Na,PO,()

Part 3

The ionic reaction is shown below.

6K+ (aq)+PO,- (aq) +3Nit (aq)+6CT (aq) → Na,PO,($)+6K+ (aq) +6CF (aq)

The net ionic reaction will be shown below.

3Ni* (aq) + PO,- (aq) → Na PO,(5)


As the constituent ions of potassium phosphate and nickel chloride swap their places, resulting in two new products are formed. The reaction is precipitation reaction which is also a type of displacement reaction. Other than precipitate, sodium phosphate is formed which is also soluble in water and hence it will also dissociate into its constituent ions in the ionic equation.

In this ionic equation, the potassium ion and chloride ion are present in the same form in both the side of the arrow of the equation and hence they are spectator ions which get cancel out and the resultant net ionic reaction can be obtained.

Answer

Part 1

The ionic reaction is shown below.Ca** (aq) +S? (aq)+Cu²+ (aq)+2CT (aq) → CuS(s)+Ca** (aq) + 2CI+ (aq)

The net ionic reaction will be shown below.

Cu²+ (aq) +S?- (aq) → CuS(s)

Part 2

The ionic reaction is shown below.

Nat (aq) +OH(aq)+H+ (aq)+NO, (aq) → H,0(1)+Na* (aq)+NO, (aq)

The net ionic reaction will be shown below.

(oʻH+ (hp) H0+(bp).H

Part 3

The ionic reaction is shown below.

6K+ (aq)+PO,- (aq) +3Nit (aq)+6CT (aq) → Na,PO,($)+6K+ (aq) +6CF (aq)

The net ionic reaction will be shown below.

3Ni* (aq) + PO,- (aq) → Na PO,(5)

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