Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: mg+2 , pb+4 , i−

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: mg+2 , pb+4 , i− , o−2

Answers

MgO
MgI2
PbO2
PbI4

These are the possible compounds

MgI₂

MgO

PbI₄

PbO₂

Explanation:

Binary compounds are formed when a cation combines with an anion. Such compounds are also known as ionic compounds.  

The four binary compounds that can be formed are as follows:

Mg²⁺ I⁻

When writing the empirical formula the charge of the anion is written as the subscript of the cation, and the charge of the cation is written as the as script of the anion, such as  

Mg₁I₂ or MgI₂

Mg²⁺ O²⁻

Mg₂O₂ or MgO

Pb⁴⁺ I⁻

Pb₁I₄ or PbI₄

Pb⁴⁺ O²⁻

Pb₂O₄ or PbO₂

$ CaCl_2$, CaS, $ Cr Cl_4$, $ CrS_2$

Explanation:

The reaction can be done by adding the cations and the anions.

The binary compounds are always formed by the two different elements.

When one calcium ion, $ Ca ^{2+} $ combines with the two calcium ions, $ Cl^-$, they formed a binary compound of $ CaCl_2$.

When one $ Ca ^{2+} $ combines with one $S^{2-}$ ion, they formed CaS binary compound.

When one chromium ion $ Cr^{4+}$ combines with four ions of chlorine, $ Cl ^- $, the compound formed is $ Cr Cl_4$.

When 1 ion of $ Cr^{4+}$ combines with 2 ions of sulphur, $S^2$, the binary compound formed is $ CrS_2$.

CaS, CaBr₂, VBr₅, and V₂S₅.

Explanation:

The ionic compound should be neutral; the overall charge of it is equal to zero.Binary ionic compound is composed of two different ions.

Ca²⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.

CaS can be formed via combining Ca²⁺ with S²⁻ to form the neutral binary ionic compound CaS.CaBr₂ can be formed via combining 1 mole of Ca²⁺ with 2 moles of Br⁻ to form the neutral binary ionic compound CaBr₂.

V⁵⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.

V₂S₅ can be formed via combining 2 moles of V⁵⁺ with 5 moles of S²⁻ to form the neutral binary ionic compound V₂S₅.VBr₅ can be formed via combining 1 mole of V⁵⁺ with 5 moles of Br⁻ to form the neutral binary ionic compound VBr₅.

So, the empirical formula of four binary ionic compounds that could be formed is: CaS, CaBr₂, VBr₅, and V₂S₅.

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written betweenZn^{2+} (Positive ion)and F^{-} (Negative ion)

First Formula would be ZnF_{2}

Second empirical formula is between Zn^{2+}(Positive ion) and O^{2-}(Negative ion)

Second Formula would be Zn_{2}O_{2}

Note : When the subscript are same they get cancel out, so Zn_{2}O_{2} would be written as ZnO

Third empirical formula is between Ni^{4+}(Positive ion) and F^{-}(Negative ion)

Third Formula would be :NiF_{4}

Forth empirical formula is between Ni^{4+}(Positive ion)and O^{2-}(negative ion)

Forth Formula would be : Ni_{2}O_{4} or NiO_{2}

Note- The subscript will be simplified and the formula will be written as NiO_{2}.

The empirical formula of four binary ionic compounds are : ZnF_{2}, ZnO, NiF_{4},NiO_{2}

Write the empirical formula of at least four binary ionic compounds that could be formed from the fo
Write the empirical formula of at least four binary ionic compounds that could be formed from the fo
Write the empirical formula of at least four binary ionic compounds that could be formed from the fo
Write the empirical formula of at least four binary ionic compounds that could be formed from the fo

The empirical formula of at least four binary ionic compounds that could be formed from the following ions:

ZnCl2 or zinc chloride

ZnS or zinc sulfide

Al2S3 or aluminum sulfide

AlCl3 or aluminum chloride

The empirical formula of at least four binary ionic compounds :

1. ZnF₂

2. Ni₂O₄ ---.>NiO₂

3. ZnO

4. NiF₄

Further explanation

Ions are atoms that have a charge

Ions are formed because events are capturing or releasing electrons.

Ions can be differentiated based on the number of constituent elements they become

1. monatomic ion, if it comes from one element, such as K⁺, Mg²⁺, Cl⁻2. polyatomic ion, if it comes from two or more elements such as PO₄³⁻, SO₄²⁻, ClO₃⁻

Based on the charge, ions can be divided into:

1. positive ion (cation)

happens if the atom releases electrons, for example

Al³⁺, ---> Al⇒ Al³⁺ + 3e⁻

Pb²⁺, ----> Pb⇒ Pb²⁺ + 2e-

2. negative ion (anion)

happens if the atom captures electrons, like

S²⁻, S + 2e⁻⇒ S²⁻

F⁻, F + e⁻⇒ F⁻

For ionic compounds consisting of cations (ions +) and anions (ions -)

The naming is preceded by the cation then the anion with the -ide suffix added

Generally for this ion compound consists of metal elements as cations and non-metals as anions

Binary ionic compounds are formed from 2 different atomic elements, namely metal and non-metal

Metals as cations are positively charged ions.

Nonmetals as anions are negatively charged ions.

Cation and anion charge numbers are placed crosswise.

From some of these ions

Possible compounds from the incorporation of these ions are ions

1. ZnF₂

2. Ni₂O₄ ---.>NiO₂

3. ZnO

4. NiF₄

Learn more

The net ionic equation

ion stability

ionic bonding

Keywords: binary ionic compounds, elements, cations, anions, polyatomic, monoatomic


Write the empirical formula of at least four binary ionic compounds that could be formed from the fo

Bynari means that the compound is formed by two kind of elements.

You have listed three ions, V 5+, Cl - and O 2-.

Binary ionic compounds are formed by a positive ion and a negative ion, so the possible ionic compound formed by the listed ions are:

1) VCl5, where the number 5 next to Cl is a subscript.

2) V2O5, where the number 2 next to V and the number 5 next to O are subscripts.

Subscripts are used to indicate the number of atoms of each element in the formula.

So, the empirical formula searched are VCl5 and V2O5.

I can give you other examples with more ions.

Ca (2+) and S(2-) => Ca2S2 => CaS

Na(+) and F(-) => NaF

Cs(+) and Br(-) => CsBr

For the answer to the question above,the Ionic compounds are the compounds consists of positive and negative ions.
Zn(2+):
ZnBr2:  
ZnS:
Al(+3):
Al203
Al2(SO4)^3
Cl:(1-)
NaCl 
I hope my answers helped you with your problem. Have a nice day!
Ionic compounds are the compounds consists of positive and negative ions.
Zn(2+):
ZnBr2:  
ZnS:
Al(+3):
Al203
Al2(SO4)^3
Cl:(1-)
NaCl 

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