An object whose moment of inertia is 4.70 kgm2 experiences the torque shown in the figure (Figure 1) .
What is the object’s angular velocity at 3.00 s? Assume it starts from rest.
-
Total angular impulse experienced by object after t = 3.0 s is: 3 m-N-s {from graph}
Avg Torque experienced by object for the entire 3.0 s period = 3 m-N-s/3 s = 1 m-N
α = Avt Torque/I = 1 m-N/4.70 kgm² = 0.2128 rad/s²
w at t = 3.00 s = αt = (0.2128)(3.00) = 0.638 rad/s ANS
Do you have questions that need to be resolved? Ask to hear answers from experts here!
Leave a Reply