Consider the system shown in the figure. Block A has weight 4.91 {rm N} and block B has weight 2.94 {rm N}. Once block B is set into downward motion, it descends at a constant speed. Assume that the mass and friction of the pulley are negligible.
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Constant speed –> a = 0 .
T = Wb
T = μ Wa
μ = Wb/Wa = 2.94/4.91 = 0.6
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