I can’t figure out how to determine how many 120deg bond angles are in C6H8? The structure looks like this
H..H..H……………..H
C=C-C-C(triple)C-C-H
H……H………………H
All the Hs have a single bond.
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Both double bonded carbons will have 120 degree bond angles.
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There are 6 120 degree bonds
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