Provide a structure for the following compound: C6H13N; IR: 3280, 1653, 898 cm–1; 1H
NMR spectrum: 2H in a doublet, 2H in a singlet, 2H in a quartet, 3H in a singlet, 3H in a doublet, 1H in a singlet
I’m think the 2H in a quartet and the 3H in a doublet would have to be Ch2-Ch3 on a central carbon with no hydrogens attached to that central carbon; I am also thinking this is a primary amine with (R-NH2); what i’m stuck on is how you can have a split 2H doublet and no splitting on the 1H singlet?
Any help would be appreciated; this question is making me angry!
2H in a doublet, 2H in a singlet, 2H in a quartet, 3H in a singlet, 3H in a doublet, 1H in a singlet
chemical shifts respectively: 4.8, 3.2, 2.6, 1.8, 1.2, 1 delta values in ppm
2H in a doublet, 2H in a singlet, 2H in a quartet, 3H in a singlet, 3H in a doublet, 1H in a singlet
chemical shifts respectively: 4.8, 3.2, 2.6, 1.8, 1.2, 1 delta values in ppm
http://s616.photobucket.com/albums/tt244/arberf001…
that’s the question and my attempt at answering
http://s616.photobucket.com/albums/tt244/arberf001…
that’s the question and my attempt at answering
i feel like my response satisfies all of the criteria. maybe i need to brush up on my 1H NMR…..
i feel like my response satisfies all of the criteria. maybe i need to brush up on my 1H NMR…..
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Is there any way you can post a picture? With the quartet – are you sure it’s a quartet, and not a hextet (ie 6 lines)?
EDIT: The thing you describe as “3H doublet” is actually a triplet. I think this compound might be CH3CH2NHCH2C(=CH2)CH3. In terms of what’s wrong with your suggestion – your double bond has three protons on it, and there are only two protons in the alkene region of the spectrum!
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No chemical shifts on the NMR spectrum??
Your formula C6H13N has one degree of unsaturation, which could be either a double bond or a cycle. But 1653 cm-1 is the IR resonance for a C=C double bond, so I’ll conclude that the molecule contains 1 double bond and no rings.
The IR resonance at 3280 cm-1 suggests a secondary amine group. That N-H group is probably the 1H singlet.
The NMR 3H singlet suggests an isolated methyl group. The ethyl group is wrong as it should be a 2H quartet and a 3H triplet. Instead, the 3H doublet would be a methyl group attached to a CH group (but then the CH group would be a quartet, and I don’t see a 1H quartet there).
Is the 2H quartet a normal quartet (1:3:3:1) or is it a doublet-of-doublets quartet (1:1:1:1)? The latter would indicate splitting by two different hydrogens.
I can’t figure out your compound either. “Easy 10 points” my #@$. 🙂
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Edit: Given your chemical shifts I’ll agree with you about its being a primary amine.
Thus, given your NMR integrals, you have one NH2, two CH3’s, two CH2’s, one CH, and one C without hydrogens in your compound. I’ve tried writing several structures, but I haven’t found one consistent with your data. 🙁 I’m still thrown off by the 3H doublet, which would suggest that there is a 1H quartet (or multiplet if it’s close to another hydrogen) somewhere.
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It looks like it is unsaturated. If you were to remove the NH2, you’d end up with C6H11, an unsaturated alkyl group. Not sure whether it is an alkene or a cycloalkane, though.
You also don’t have a CH3-CH2 group in the molecule, judging by the NMR, since the CH3 would be split into a triplet, not a doublet.
Have you any chemical shift values for the NMR? I can’t make heads nor tails of these figures.
Edit: you have a triplet 3H, not a doublet. This would point towards an ethyl group. The broad singlet could be a secondary amine proton, which tend to occur as singlets due to proton-deuteron exchange. This could explain the doublet for the 2H.
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